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-Huh. Miller play guitar make noise. Miller
-- In , "Marty Tippens" <mctippens@e...>
wrote:
>
> Gavin,
>
> Are you assuming a radius of 10" or a diameter of 10"?
>
> A 10" speaker has a radius of 5". Using the surface area formula
for a cone, (Pi)(r)(s), we have approximately (3.14)(5)(5.6) = 84.78
sq inches. I'm being conservative and assuming that the depth to the
dome is 2" and that if it were a complete cone, the depth to the tip
of the cone would be about 2.5". By the Pythagorean theorem, s would
be 5.6".
>
> It's not going to be much different figuring with a 1" diameter
dome. Using [(Pi)(R)(S) - (Pi)(r)(s)] + (Pi) r^2 where R is the
radius of the speaker, r is the 2d radius of the dome (not the
spherical radius), S is the slant height of the speaker, s is the
slant height of the section of the cone removed due to the center
dome.
>
> [(3.14)(5)(5.6) - (3.14)(.5)(.707)] + (3.14)(.5)^2 = 87.59 square
inches. This is using approximated values but actual values aren't
going to be different enough to jump the surface area from 87 sq
inches up to 163 sq inches.
>
> -Marty
>
>
>
>
> ----- Original Message -----
> From: Gavin Ehringer
> To:
> Sent: Saturday, November 27, 2004 11:25 AM
> Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus 10" -
some thoughts...
>
>
>
> No, these are the correct calculations for surface area in square
inches, based on the
> radius of each cone.
>
> Run the calculations and you shall see!
>
> Gavin
>
>
> --- In , "Marty Tippens"
<mctippens@e...> wrote:
> > It has to be square inches given that every other dimension is
given in square inches
> BUT they can't be for a single speaker. They look about right for
pairs of speakers at each
> given diameter. I don't see the rest of Gavin's details in your
edit of his post.
> >
> > -Marty
> > ----- Original Message -----
> > From: pwrose@j...
> > To:
> > Sent: Saturday, November 27, 2004 4:58 AM
> > Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus
10" - some thoughts...
> >
> >
> > On Fri, 26 Nov 2004 16:04:20 -0000 "Gavin Ehringer"
> > <gavinehringer@e...> writes:
> > > SNIP<
> > > 10" = 163 sq @ 2" depth.
> > > 12" = 244.sq. @ 3" depth.
> > > 15" = 382. sq @ 4.5" depth.
> > ~~~~~~~~~~~~~~~~~~~~~~~
> > Gavin,
> >
> > sq. what?
> > can't be inches.
> >
> > Bill
> >
> >
> > .
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The error comes in that my calculation of the surface area of a cone included
the base. So,
yes, Marty, you are correct.
Gavin
> > Gavin,
> >
> > Are you assuming a radius of 10" or a diameter of 10"?
> >
> > A 10" speaker has a radius of 5". Using the surface area formula
> for a cone, (Pi)(r)(s), we have approximately (3.14)(5)(5.6) = 84.78
> sq inches. I'm being conservative and assuming that the depth to the
> dome is 2" and that if it were a complete cone, the depth to the tip
> of the cone would be about 2.5". By the Pythagorean theorem, s would
> be 5.6".
> >
> > It's not going to be much different figuring with a 1" diameter
> dome. Using [(Pi)(R)(S) - (Pi)(r)(s)] + (Pi) r^2 where R is the
> radius of the speaker, r is the 2d radius of the dome (not the
> spherical radius), S is the slant height of the speaker, s is the
> slant height of the section of the cone removed due to the center
> dome.
> >
> > [(3.14)(5)(5.6) - (3.14)(.5)(.707)] + (3.14)(.5)^2 = 87.59 square
> inches. This is using approximated values but actual values aren't
> going to be different enough to jump the surface area from 87 sq
> inches up to 163 sq inches.
> >
> > -Marty
> >
> >
> >
> >
> > ----- Original Message -----
> > From: Gavin Ehringer
> > To:
> > Sent: Saturday, November 27, 2004 11:25 AM
> > Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus 10" -
> some thoughts...
> >
> >
> >
> > No, these are the correct calculations for surface area in square
> inches, based on the
> > radius of each cone.
> >
> > Run the calculations and you shall see!
> >
> > Gavin
> >
> >
> > --- In , "Marty Tippens"
> <mctippens@e...> wrote:
> > > It has to be square inches given that every other dimension is
> given in square inches
> > BUT they can't be for a single speaker. They look about right for
> pairs of speakers at each
> > given diameter. I don't see the rest of Gavin's details in your
> edit of his post.
> > >
> > > -Marty
> > > ----- Original Message -----
> > > From: pwrose@j...
> > > To:
> > > Sent: Saturday, November 27, 2004 4:58 AM
> > > Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus
> 10" - some thoughts...
> > >
> > >
> > > On Fri, 26 Nov 2004 16:04:20 -0000 "Gavin Ehringer"
> > > <gavinehringer@e...> writes:
> > > > SNIP<
> > > > 10" = 163 sq @ 2" depth.
> > > > 12" = 244.sq. @ 3" depth.
> > > > 15" = 382. sq @ 4.5" depth.
> > > ~~~~~~~~~~~~~~~~~~~~~~~
> > > Gavin,
> > >
> > > sq. what?
> > > can't be inches.
> > >
> > > Bill
> > >
> > >
> > > .
> > > Visit for
> archived messages,
> > bookmarks, files, polls, etc.
> > >
> > >
> > >
> > > Yahoo! Groups Sponsor
> > > ADVERTISEMENT
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> Terms of Service.
> > >
> > >
> > >
> > > [Non-text portions of this message have been removed]
> >
> >
> >
> >
> >
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> > [Non-text portions of this message have been removed]
Oh, ok. Yes, we don't want to put that base in front of the speaker (tee he he).
-Marty
----- Original Message -----
From: Gavin Ehringer
To:
Sent: Sunday, November 28, 2004 10:24 AM
Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus 10" - some
thoughts...
The error comes in that my calculation of the surface area of a cone included
the base. So,
yes, Marty, you are correct.
Gavin
> > Gavin,
> >
> > Are you assuming a radius of 10" or a diameter of 10"?
> >
> > A 10" speaker has a radius of 5". Using the surface area formula
> for a cone, (Pi)(r)(s), we have approximately (3.14)(5)(5.6) = 84.78
> sq inches. I'm being conservative and assuming that the depth to the
> dome is 2" and that if it were a complete cone, the depth to the tip
> of the cone would be about 2.5". By the Pythagorean theorem, s would
> be 5.6".
> >
> > It's not going to be much different figuring with a 1" diameter
> dome. Using [(Pi)(R)(S) - (Pi)(r)(s)] + (Pi) r^2 where R is the
> radius of the speaker, r is the 2d radius of the dome (not the
> spherical radius), S is the slant height of the speaker, s is the
> slant height of the section of the cone removed due to the center
> dome.
> >
> > [(3.14)(5)(5.6) - (3.14)(.5)(.707)] + (3.14)(.5)^2 = 87.59 square
> inches. This is using approximated values but actual values aren't
> going to be different enough to jump the surface area from 87 sq
> inches up to 163 sq inches.
> >
> > -Marty
> >
> >
> >
> >
> > ----- Original Message -----
> > From: Gavin Ehringer
> > To:
> > Sent: Saturday, November 27, 2004 11:25 AM
> > Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus 10" -
> some thoughts...
> >
> >
> >
> > No, these are the correct calculations for surface area in square
> inches, based on the
> > radius of each cone.
> >
> > Run the calculations and you shall see!
> >
> > Gavin
> >
> >
> > --- In , "Marty Tippens"
> <mctippens@e...> wrote:
> > > It has to be square inches given that every other dimension is
> given in square inches
> > BUT they can't be for a single speaker. They look about right for
> pairs of speakers at each
> > given diameter. I don't see the rest of Gavin's details in your
> edit of his post.
> > >
> > > -Marty
> > > ----- Original Message -----
> > > From: pwrose@j...
> > > To:
> > > Sent: Saturday, November 27, 2004 4:58 AM
> > > Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus
> 10" - some thoughts...
> > >
> > >
> > > On Fri, 26 Nov 2004 16:04:20 -0000 "Gavin Ehringer"
> > > <gavinehringer@e...> writes:
> > > > SNIP<
> > > > 10" = 163 sq @ 2" depth.
> > > > 12" = 244.sq. @ 3" depth.
> > > > 15" = 382. sq @ 4.5" depth.
> > > ~~~~~~~~~~~~~~~~~~~~~~~
> > > Gavin,
> > >
> > > sq. what?
> > > can't be inches.
> > >
> > > Bill
> > >
> > >
> > > .
> > > Visit for
> archived messages,
> > bookmarks, files, polls, etc.
> > >
> > >
> > >
> > > Yahoo! Groups Sponsor
> > > ADVERTISEMENT
> > >
> > >
> > >
> > >
> > >
> > >
> > ------------------------------------------------------------------
> ----------
> > --
> > > Yahoo! Groups Links
> > >
> > > a.. To visit your group on the web, go to:
> > >
> > >
> > > b.. To unsubscribe from this group, send an email to:
> > >
> > >
> > > c.. Your use of Yahoo! Groups is subject to the Yahoo!
> Terms of Service.
> > >
> > >
> > >
> > > [Non-text portions of this message have been removed]
> >
> >
> >
> >
> >
> > .
> > Visit for archived
> messages, bookmarks, files, polls, etc.
> >
> >
> >
> > Yahoo! Groups Sponsor
> > ADVERTISEMENT
> >
> >
> >
> >
> >
> > --------------------------------------------------------------------
> ----------
> > Yahoo! Groups Links
> >
> > a.. To visit your group on the web, go to:
> >
> >
> > b.. To unsubscribe from this group, send an email to:
> >
> >
> > c.. Your use of Yahoo! Groups is subject to the Yahoo! Terms of
> Service.
> >
> >
> >
> > [Non-text portions of this message have been removed]
.
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