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Gavin,
Are you assuming a radius of 10" or a diameter of 10"?
A 10" speaker has a radius of 5". Using the surface area formula for a cone,
(Pi)(r)(s), we have approximately (3.14)(5)(5.6) = 84.78 sq inches. I'm being
conservative and assuming that the depth to the dome is 2" and that if it were a
complete cone, the depth to the tip of the cone would be about 2.5". By the
Pythagorean theorem, s would be 5.6".
It's not going to be much different figuring with a 1" diameter dome. Using
[(Pi)(R)(S) - (Pi)(r)(s)] + (Pi) r^2 where R is the radius of the speaker, r is
the 2d radius of the dome (not the spherical radius), S is the slant height of
the speaker, s is the slant height of the section of the cone removed due to the
center dome.
[(3.14)(5)(5.6) - (3.14)(.5)(.707)] + (3.14)(.5)^2 = 87.59 square inches. This
is using approximated values but actual values aren't going to be different
enough to jump the surface area from 87 sq inches up to 163 sq inches.
-Marty
----- Original Message -----
From: Gavin Ehringer
To:
Sent: Saturday, November 27, 2004 11:25 AM
Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus 10" - some
thoughts...
No, these are the correct calculations for surface area in square inches,
based on the
radius of each cone.
Run the calculations and you shall see!
Gavin
--- In , "Marty Tippens" <mctippens@e...> wrote:
> It has to be square inches given that every other dimension is given in
square inches
BUT they can't be for a single speaker. They look about right for pairs of
speakers at each
given diameter. I don't see the rest of Gavin's details in your edit of his
post.
>
> -Marty
> ----- Original Message -----
> From: pwrose@j...
> To:
> Sent: Saturday, November 27, 2004 4:58 AM
> Subject: [SurfGuitar101] Re: 15" Speakers versus 12" versus 10" - some
thoughts...
>
>
> On Fri, 26 Nov 2004 16:04:20 -0000 "Gavin Ehringer"
> <gavinehringer@e...> writes:
> > SNIP<
> > 10" = 163 sq @ 2" depth.
> > 12" = 244.sq. @ 3" depth.
> > 15" = 382. sq @ 4.5" depth.
> ~~~~~~~~~~~~~~~~~~~~~~~
> Gavin,
>
> sq. what?
> can't be inches.
>
> Bill
>
>
> .
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