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Boy Brian, I am impressed....one question, in the case
of a Jazzmaster, Jaguar, or any other guitar where the
strings pass over a bridge and are anchored behind as
say the mentioned, doesn't this additional length add
an additional variable to your equation.....I'm no
math wizard.....but I like tight strings.....with the
additional string length we have both mentioned, I do
know that I can get away with literally no relief in
the neck which translates into a really low string
action.....this is good ya? my beloved Jazzmasters
end up with a fightenly low action. Smooth as a
baby's fanny......Probably the reason I'll pick one of
them up first every time......I need all the help I
can get.......eddie k
--- Brian Neal <> wrote:
> If you want to be a total geek about it, the
> classical formula for the
> frequency of a vibrating string is:
>
> f = (1 / 2L) * SQRT(T / u)
>
> where
> f = frequency
> L = length of the string
> T = tension
> u = linear density of the string
>
> So lets say we play open A on a Strat. In order to
> play the same
> pitched open A on a shorter scale Jaguar (smaller L)
> with the same
> type of strings, we need to make T smaller to make
> everything equal
> out. So the the tension on shorter scale guitars is
> a bit lower IF you
> use the same type of strings (same density).
>
> The above analysis ignores the break angle over the
> bridge..it just
> assumes the string is fixed at 2 points. You could
> probably assume
> that for a strat, but maybe not for a
> Jazzmaster/Jaguar. That
> complicates things further :-)
>
> BN
> (former Physics minor)
>
>
>
>
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